During a thermodynamic process, the increase in internal energy of a system is equal to the work done on the system. Which process does the system undergo?

In summer,when the valve of a bicycle tube is removed,the escaping air appears cold. Why?

The pressure $P_{1}$ and density $d_{1}$ of a diatomic gas $\left(\gamma = \frac{7}{5}\right)$ change suddenly to $P_{2} (> P_{1})$ and $d_{2}$ respectively during an adiabatic process. The temperature of the gas increases and becomes $......$ times its initial temperature. (Given $\frac{d_{2}}{d_{1}} = 32$)

$A$ diatomic ideal gas is compressed adiabatically to $\frac{1}{32}$ of its initial volume. If the initial temperature of the gas is $T_1$ (in Kelvin) and the final temperature is $a T_1$,the value of $a$ is

$A$ gas is compressed adiabatically until its temperature is doubled. The ratio of its final volume to initial volume will be

For an adiabatic process,the wrong statement is: