(B) The given equation is $x^3-6x^2+6x-5=0$. To shift the roots by $h$,we replace $x$ with $x+h$. The new equation becomes $(x+h)^3-6(x+h)^2+6(x+h)-5=

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(B) The given equation is $x^3-6x^2+6x-5=0$. To shift the roots by $h$,we replace $x$ with $x+h$. The new equation becomes $(x+h)^3-6(x+h)^2+6(x+h)-5=0$. Expanding the terms: $(x^3+3x^2h+3xh^2+h^3) - 6(x^2+2xh+h^2) + 6(x+h) - 5 = 0$. Grouping the terms by powers of $x$: $x^3 + (3h-6)x^2 + (3h^2-12h+6)x + (h^3-6h^2+6h-5) = 0$. For the $x^2$ term to be absent,its coefficient must be zero: $3h-6 = 0$. Therefore,$h = 2$.

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Each of the roots of the equation $x^3-6x^2+6x-5=0$ is increased by $h$. If the new transformed equation does not contain the $x^2$ term,then $h$ is equal to:

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A
$1$
B
$2$
C
$\frac{1}{2}$
D
$\frac{1}{3}$

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Each of the roots of the equation $x^3-6x^2+6x-5=0$ is increased by $h$. If the new transformed equation does not contain the $x^2$ term,then $h$ is equal to:

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