The effective capacitance between $A$ and $B$ in the shown figure is (all capacitances are in $\mu F$):

The equivalent capacitance of three capacitors of capacitance $C_1, C_2$ and $C_3$ connected in parallel is $12$ units and their product is $C_1 \cdot C_2 \cdot C_3 = 48$. When the capacitors $C_1$ and $C_2$ are connected in parallel,the equivalent capacitance is $6$ units. Then the capacitances are:

$A$ capacitance of $2\ \mu F$ is required in an electrical circuit across a potential difference of $1.0\ kV$. $A$ large number of $1\ \mu F$ capacitors are available which can withstand a potential difference of not more than $300\ V$. The minimum number of capacitors required to achieve this is

Three capacitors of capacitance $1\ \mu F$,$2\ \mu F$,and $3\ \mu F$ are connected in series,and a potential difference of $11\ V$ is applied across the combination. The potential difference across the plates of the $1\ \mu F$ capacitor is......$V$.

$A$ system of $2$ capacitors of capacitance $2 \mu F$ and $4 \mu F$ is connected in series across a potential difference of $6 \text{ V}$. The electric charge and energy stored in the system are

In the figure,the area of each plate is $A$ and the distance between consecutive plates is as shown in the figure. What is the effective capacitance between points $A$ and $B$?