Ethanol (C_2H_5OH) and formic acid (HCO_2H) c | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) $1$. Ethanol $(C_2H_5OH)$ is a primary alcohol,while formic acid $(HCO_2H)$ is a carboxylic acid with an aldehyde-like group $(-CHO)$.$2$. Tollen'

Vedclass · Accepted Answer

Hot acidic $KMnO_4$ solution

Vedclass · Answer

(B) $1$. Ethanol $(C_2H_5OH)$ is a primary alcohol,while formic acid $(HCO_2H)$ is a carboxylic acid with an aldehyde-like group $(-CHO)$.$2$. Tollen's reagent,Fehling solution,and $HgCl_2$ solution are oxidizing agents that react with the $-CHO$ group present in formic acid to give positive tests (e.g.,silver mirror,red precipitate,or white precipitate),whereas ethanol does not react with these reagents.$3$. Hot acidic $KMnO_4$ solution is a strong oxidizing agent that oxidizes both ethanol (to acetic acid) and formic acid (to $CO_2$ and $H_2O$).$4$. Since both compounds react with hot acidic $KMnO_4$,this reagent cannot be used to distinguish between them.

Ethanol $(C_2H_5OH)$ and formic acid $(HCO_2H)$ cannot be distinguished by:

Similar Questions

$CH_3-CO-CH_2-COOC_2H_5 \xrightarrow{NaOH, H_2O} A$. The product '$A$' in the reaction is

$CH_3COOH \xrightarrow{LiAlH_4} A$
$A + CH_3COOH \xrightarrow{H_3O^+} B + H_2O$
In the above reactions,'$A$' and '$B$' respectively are:

Which of the following pairs of compounds can be differentiated by $NaHCO_3$ as well as by $NaOH$?

Which of the following compounds evolves $2 \ mole$ of $CO_2$ on gentle heating?

Ethyl ester $\xrightarrow{CH_3MgBr \text{ (excess)}} P$. The product $P$ will be

Vedclass Test Series

Exam Paper Generator

Online Exam Module