Ethanol cannot be dried by anhydrous CaCl_2 d | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) Anhydrous $CaCl_2$ is a common drying agent for many organic solvents. However,it cannot be used to dry ethanol because it reacts with ethanol to

Vedclass · Accepted Answer

$CaCl_2 \cdot 2C_2H_5OH$

Vedclass · Answer

(A) Anhydrous $CaCl_2$ is a common drying agent for many organic solvents. However,it cannot be used to dry ethanol because it reacts with ethanol to form a stable solvated complex. The reaction is: $CaCl_2 + 4C_2H_5OH \rightarrow CaCl_2 \cdot 4C_2H_5OH$. Among the given options,the complex $CaCl_2 \cdot 4C_2H_5OH$ is the standard solvated product,but since the question asks for the specific solvated product formed in this context,and based on standard chemical literature,the correct adduct is $CaCl_2 \cdot 4C_2H_5OH$. Given the options provided,there is a discrepancy in the stoichiometry. However,$CaCl_2$ forms adducts with alcohols similar to how it forms hydrates. Assuming the question implies the formation of a stable adduct,the correct answer is $CaCl_2 \cdot 4C_2H_5OH$,but since it is not listed,we identify that $CaCl_2$ forms adducts with ethanol.

Ethanol cannot be dried by anhydrous $CaCl_2$ due to the formation of the following solvated product:

Similar Questions

$CH_3-CH_2-CH=CH_2$ $\xrightarrow[CCl_4]{HCl} X$ $\xrightarrow{Aq. NaOH} Y$ $\xrightarrow[\Delta]{Conc. H_3PO_4} Z$
The major product $Z$ is:

The product formed in the following multistep reaction is:

Which of the following oxidation reactions can be carried out with chromic acid in aqueous acetone at $5 - 10^{\circ}C$?

Lucas test is used for:

An organic compound $X$ is oxidised by using acidified $K_{2}Cr_{2}O_{7}$. The product obtained reacts with phenyl hydrazine but does not answer the silver mirror test. The possible structure of $X$ is

Vedclass Test Series

Exam Paper Generator

Online Exam Module