Ethanol reacts with H_2SO_4 at 140^circ C to | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) When ethanol $(CH_3CH_2OH)$ is heated with concentrated $H_2SO_4$ at $140^\circ C$ $(413 \ K)$,it undergoes intermolecular dehydration to form die

Vedclass · Accepted Answer

Ethoxy ethane

Vedclass · Answer

(C) When ethanol $(CH_3CH_2OH)$ is heated with concentrated $H_2SO_4$ at $140^\circ C$ $(413 \ K)$,it undergoes intermolecular dehydration to form diethyl ether (ethoxy ethane).The reaction is as follows:$2CH_3CH_2OH \xrightarrow{conc. H_2SO_4, 140^\circ C} CH_3CH_2-O-CH_2CH_3 + H_2O$Mechanism:$1$. Protonation of ethanol: $CH_3CH_2OH + H^+ \rightarrow CH_3CH_2OH_2^+$$2$. Nucleophilic attack: $CH_3CH_2OH_2^+ + CH_3CH_2OH \rightarrow CH_3CH_2-O^+(H)-CH_2CH_3 + H_2O$$3$. Deprotonation: $CH_3CH_2-O^+(H)-CH_2CH_3 \rightarrow CH_3CH_2-O-CH_2CH_3 + H^+$

Ethanol reacts with $H_2SO_4$ at $140^\circ C$ to form

Similar Questions

Identify the missing product in the following reaction: $C_6H_5ONa + CH_3CH_2Br \rightarrow (?)$

The $IUPAC$ name of an unsymmetrical ether with the molecular formula $= C_4H_{10}O$ is:

Predict the major products of the following reaction:
$m$-methoxyphenethyl$-1-$phenylethyl ether + $HI$ (excess) $\xrightarrow{\text{heat}}$ ?

The value of $n$ in the given reaction is:

Acetyl chloride does not react with

Vedclass Test Series

Exam Paper Generator

Online Exam Module