Explain the different oxidation reactions of aldehydes and ketones.

Vedclass pdf generator app on play store
Vedclass iOS app on app store
(N/A) $1$. Oxidation of Aldehydes: Aldehydes are easily oxidized to carboxylic acids with the same number of carbon atoms using common oxidizing agents like $KMnO_4$,$K_2Cr_2O_7$,or even mild agents like $Tollens'$ reagent and $Fehling's$ solution. The reaction is: $R-CHO + [O] \rightarrow R-COOH$.
$2$. Oxidation of Ketones: Ketones are generally resistant to oxidation under normal conditions. They require strong oxidizing agents (like concentrated $HNO_3$ or $KMnO_4$ at high temperatures) and undergo cleavage of $C-C$ bonds to form a mixture of carboxylic acids with fewer carbon atoms than the original ketone. The reaction follows $Popoff's$ rule.

Explore More

Similar Questions

$(C_2H_5O)_2CO \xrightarrow[H_3O^{+}]{CH_3MgBr(\text{excess})} A$. $A$ (alcohol) can also be obtained by:

The major product $'P'$ formed in this reaction is:

$OCH-CHO \xrightarrow{OH^{-}} HOCH_2-COO^-$. The reaction given is:

The major product formed in the following reaction is:

$Propyne$ $\xrightarrow[Hg^{2+} / H_2 O, \Delta]{H^{+}}$ $P$ $\stackrel{Ba(OH)_2}{\rightleftharpoons}$ $Q$ $\xrightarrow{\Delta}$ $R$. $R$ in the above sequence of reactions is:

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo