Explain solid-vapour equilibrium by example.

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(N/A) At constant temperature in a closed vessel,the system where a solid sublimes to the vapour phase is known as solid-vapour equilibrium.
$Ex.-1$: If we place solid iodine $(I_2)$ in a closed vessel,after some time the vessel gets filled with violet vapour and the intensity of the colour increases with time. After a certain time,the intensity of the colour becomes constant,and at this stage,equilibrium is attained. Hence,solid iodine sublimes to give iodine vapour,and the iodine vapour condenses to give solid iodine. Properties,colours,etc.,become constant. The equilibrium can be represented as:
$I_{2(s)} \rightleftharpoons I_{2(g)}$ (at constant $T$)
(violet solid) $\rightleftharpoons$ (violet vapour)
Other examples showing this kind of equilibrium are:
$(i)$ $\text{Camphor}_{(s)} \rightleftharpoons \text{Camphor}_{(g)}$ (at constant $T$)
$(ii)$ $NH_4Cl_{(s)} \rightleftharpoons NH_4Cl_{(g)}$ (at constant $T$)

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Similar Questions

Which of the following statements is not correct about the equilibrium constant $K_c$?

In the chemical reaction $A \rightleftharpoons B$,the system will be known to be in equilibrium when:

$A$ liquid is in equilibrium with its vapour in a sealed container at a fixed temperature. The volume of the container is suddenly increased.
$(a)$ What is the initial effect of the change on vapour pressure?
$(b)$ How do rates of evaporation and condensation change initially?
$(c)$ What happens when equilibrium is restored finally and what will be the final vapour pressure?

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When the rate of the forward reaction becomes equal to the rate of the backward reaction,this state is termed as:

Predict which of the following reactions will have an appreciable concentration of both reactants and products:
$(a)$ $Cl_{2(g)} \longleftrightarrow 2Cl_{(g)};$ $K_{c}=5 \times 10^{-39}$
$(b)$ $Cl_{2(g)}+2NO_{(g)} \longleftrightarrow 2NOCl_{(g)};$ $K_{c}=3.7 \times 10^{8}$
$(c)$ $Cl_{2(g)}+2NO_{2(g)} \longleftrightarrow 2NO_{2}Cl_{(g)};$ $K_{c}=1.8$

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