Explain the lanthanoid contraction.

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(N/A) In the lanthanoid series,there is an overall decrease in the atomic and ionic radii as the atomic number increases. This phenomenon is called lanthanoid contraction and is a unique feature in the chemistry of lanthanoids.
Reason for lanthanoid contraction:
As we move from cerium $(Ce)$ to lutetium $(Lu)$,the nuclear charge increases with the increase in atomic number,and electrons are added to the $4f$ orbital successively.
The shielding of one $4f$-electron by another is very poor due to the diffuse shape of $4f$-orbitals,even poorer than that of $d$-electrons.
As a result,the effective nuclear charge experienced by the $4f$-electrons increases,which causes a reduction in the size of the atom or ion.
The nuclear charge steadily increases with the atomic number,and there is a constant decrease in the size of the atom/ion because of the poor shielding effect of the $4f$-electrons. This is known as lanthanoid contraction.
The decrease in size is more pronounced in the case of tripositive ions $(Ln^{3+})$ than in neutral atoms.

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Which of the following statements regarding Lanthanides is false?

Which one of the following is a radioactive lanthanide?

Identify all the correct statements for Lanthanide contraction.
$(A)$ The covalent properties of the Lanthanide metal hydroxides increase from $La$ to $Lu$.
$(B)$ The chemical reactivity decreases from $La$ to $Lu$.
$(C)$ $La(OH)_3$ is more basic than $Lu(OH)_3$.
$(D)$ $Zr$ and $Hf$ have about the same radius.
$(E)$ Separation of Lanthanides from one another is easy.

Assertion : Ionisation enthalpies of the early actinoids are lower than for early lanthanoids.
Reason : $5f$ electrons are more effectively shielded from nuclear charge than $4f$ electrons.

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$(i) La(OH)_3$ is the least basic among lanthanide hydroxides. $(ii) Zr^{4+}$ and $Hf^{4+}$ have almost identical ionic radii. $(iii) Ce^{4+}$ can act as an oxidizing agent. Which of the above statements are correct?

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