Express $\sin 67^{\circ} + \cos 75^{\circ}$ in terms of trigonometric ratios of angles between $0^{\circ}$ and $45^{\circ}$.

(N/A) To express the given expression in terms of trigonometric ratios of angles between $0^{\circ}$ and $45^{\circ}$,we use the complementary angle identities:
$\sin(90^{\circ} - \theta) = \cos \theta$
$\cos(90^{\circ} - \theta) = \sin \theta$
Given expression: $\sin 67^{\circ} + \cos 75^{\circ}$
Step $1$: Rewrite $67^{\circ}$ as $(90^{\circ} - 23^{\circ})$ and $75^{\circ}$ as $(90^{\circ} - 15^{\circ})$.
$= \sin(90^{\circ} - 23^{\circ}) + \cos(90^{\circ} - 15^{\circ})$
Step $2$: Apply the complementary angle identities.
$= \cos 23^{\circ} + \sin 15^{\circ}$
Since $23^{\circ}$ and $15^{\circ}$ are both between $0^{\circ}$ and $45^{\circ}$,the expression is now in the required form.