Factorise:x^{2}+9x+18 | vedclass

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Question

(A) To factorise the quadratic expression $x^{2}+9x+18$,we need to find two numbers $p$ and $q$ such that their sum $p+q = 9$ and their product $pq =

Vedclass · Accepted Answer

$(x+6)(x+3)$

Vedclass · Answer

(A) To factorise the quadratic expression $x^{2}+9x+18$,we need to find two numbers $p$ and $q$ such that their sum $p+q = 9$ and their product $pq = 18$.By observing the factors of $18$,we find that $6+3 = 9$ and $6 	imes 3 = 18$.Now,we split the middle term $9x$ as $6x + 3x$:$x^{2}+9x+18 = x^{2}+6x+3x+18$Next,we group the terms and factor out the common terms:$= x(x+6) + 3(x+6)$Finally,taking $(x+6)$ as a common factor:$= (x+6)(x+3)$

Factorise:
$x^{2}+9x+18$

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Factorise:$x^{2}+9x+18$