Factorise : 4 x^{2}+4 x y-3 y^{2} | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) To factorise the quadratic expression $4 x^{2}+4 x y-3 y^{2}$,we use the splitting the middle term method.We need to find two numbers whose produc

Vedclass · Accepted Answer

$(2x + 3y)(2x - y)$

Vedclass · Answer

(B) To factorise the quadratic expression $4 x^{2}+4 x y-3 y^{2}$,we use the splitting the middle term method.We need to find two numbers whose product is $(4) 	imes (-3) = -12$ and whose sum is $4$.These two numbers are $6$ and $-2$.Now,rewrite the middle term $4xy$ as $6xy - 2xy$:$4 x^{2}+6 x y-2 x y-3 y^{2}$Group the terms:$= (4 x^{2}+6 x y) - (2 x y+3 y^{2})$Factor out the common terms from each group:$= 2 x(2 x+3 y)-y(2 x+3 y)$Finally,factor out the common binomial $(2 x+3 y)$:$= (2 x+3 y)(2 x-y)$

Factorise $: 4 x^{2}+4 x y-3 y^{2}$

Similar Questions

Factorise the following quadratic polynomial by splitting the middle term:
$x^{2}-12x+20$

Find the value of $x^{3}-8 y^{3}-36 x y-216$,when $x=2 y+6$.

Give possible expressions for the length and breadth of a rectangle whose area is given as $(20 x^{2}+22 x+6)$ square units,where $(x > 0)$.

Factorise $x^{2}+9 y^{2}+4+6 x y+12 y+4 x$.

Find the value of $m$ so that $2x - 1$ is a factor of $8x^4 + 4x^3 - 16x^2 + 10x + m$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module