(A) To factorise the expression $9x^{2} + 42x + 49$,we observe that it follows the algebraic identity $(a + b)^{2} = a^{2} + 2ab + b^{2}$.We can rewri

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(A) To factorise the expression $9x^{2} + 42x + 49$,we observe that it follows the algebraic identity $(a + b)^{2} = a^{2} + 2ab + b^{2}$.We can rewrite the expression as:$9x^{2} + 42x + 49 = (3x)^{2} + 2(3x)(7) + (7)^{2}$.Here,$a = 3x$ and $b = 7$.Therefore,the expression simplifies to $(3x + 7)^{2}$.