Factorize the following polynomial: p(x) = 25 | vedclass

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(C) To factorize the polynomial $p(x) = 25x^2 - 40x + 16$,we observe that it is in the form of the algebraic identity $a^2 - 2ab + b^2 = (a - b)^2$.He

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$(5x - 4)^2$

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(C) To factorize the polynomial $p(x) = 25x^2 - 40x + 16$,we observe that it is in the form of the algebraic identity $a^2 - 2ab + b^2 = (a - b)^2$.Here,$25x^2 = (5x)^2$,so $a = 5x$.Also,$16 = 4^2$,so $b = 4$.Checking the middle term: $-2ab = -2(5x)(4) = -40x$,which matches the given polynomial.Therefore,$25x^2 - 40x + 16 = (5x)^2 - 2(5x)(4) + 4^2 = (5x - 4)^2$.

Factorize the following polynomial: $p(x) = 25x^2 - 40x + 16$.

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