Fifty seeds were selected at random from each of $5$ bags of seeds,and were kept under standardised conditions favourable to germination. After $20$ days,the number of seeds which had germinated in each collection were counted and recorded as follows:
Bag $1$ $2$ $3$ $4$ $5$ Number of seeds germinated $40$ $48$ $42$ $39$ $41$
What is the probability of germination of
$(i)$ more than $40$ seeds in a bag?
$(ii)$ $49$ seeds in a bag?
$(iii)$ more than $35$ seeds in a bag?
| Bag | $1$ | $2$ | $3$ | $4$ | $5$ |
| Number of seeds germinated | $40$ | $48$ | $42$ | $39$ | $41$ |
What is the probability of germination of
$(i)$ more than $40$ seeds in a bag?
$(ii)$ $49$ seeds in a bag?
$(iii)$ more than $35$ seeds in a bag?
(A-D) The total number of bags is $5$.
$(i)$ The number of bags in which more than $40$ seeds germinated is $3$ (Bags $2, 3,$ and $5$).
Probability $= \frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}} = \frac{3}{5} = 0.6$.
$(ii)$ The number of bags in which $49$ seeds germinated is $0$.
Probability $= \frac{0}{5} = 0$.
$(iii)$ The number of bags in which more than $35$ seeds germinated is $5$ (All bags).
Probability $= \frac{5}{5} = 1$.
$(i)$ The number of bags in which more than $40$ seeds germinated is $3$ (Bags $2, 3,$ and $5$).
Probability $= \frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}} = \frac{3}{5} = 0.6$.
$(ii)$ The number of bags in which $49$ seeds germinated is $0$.
Probability $= \frac{0}{5} = 0$.
$(iii)$ The number of bags in which more than $35$ seeds germinated is $5$ (All bags).
Probability $= \frac{5}{5} = 1$.
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