The figure shows a combination of logic gates | vedclass

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(C) Let the inputs to the two $NOT$ gates be $A$ and $B$. The outputs of the $NOT$ gates are $\bar{A}$ and $\bar{B}$ respectively. These outputs are f

Vedclass · Accepted Answer

$EX-OR$

Vedclass · Answer

(C) Let the inputs to the two $NOT$ gates be $A$ and $B$. The outputs of the $NOT$ gates are $\bar{A}$ and $\bar{B}$ respectively. These outputs are fed into an $EX-OR$ gate. The output $Y$ of the $EX-OR$ gate is given by the Boolean expression: $Y = \bar{A} \oplus \bar{B}$ Using the property of the $EX-OR$ gate,$X \oplus Y = X\bar{Y} + \bar{X}Y$,we get: $Y = \bar{A}(\overline{\bar{B}}) + (\overline{\bar{A}})\bar{B}$ $Y = \bar{A}B + A\bar{B}$ This is the Boolean expression for an $EX-OR$ gate. Therefore,the given combination is equivalent to an $EX-OR$ gate.

$A$	$B$	$Y$
$0$	$0$	$1$
$0$	$1$	$0$
$1$	$0$	$0$
$1$	$1$	$1$

The figure shows a combination of logic gates. To what single gate is this combination equivalent?

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