Fill in the blanks: The possible value of the resistance of an ammeter is ...... and the possible value of the resistance of a voltmeter is ..... . (more,less)

The current passing through the galvanometer is $4\%$ of the total current in the circuit. If the resistance of the galvanometer is $G$, the shunt resistance $S$ connected across the galvanometer is:

$A$ milliammeter of range $10 \, mA$ has a coil of resistance $1 \, \Omega$. To use it as a voltmeter of range $10 \, V$,the resistance that must be connected in series with it will be ............. $\Omega$.

$A$ galvanometer coil has a resistance of $990 \,\Omega$. It shows a full-scale deflection for a current of $10 \,mA$. Calculate the value of the shunt resistance required to convert it into an ammeter of range $1 \,A$.

$A$ galvanometer,having a resistance of $50 \Omega$,gives a full scale deflection for a current of $0.05 \text{ A}$. The length in metre of a resistance wire of area of cross-section $2.97 \times 10^{-2} \text{ cm}^2$ that can be used to convert the galvanometer into an ammeter which can read a maximum of $5 \text{ A}$ current is: (Specific resistance of the wire $= 5 \times 10^{-7} \Omega\text{-m}$)

If only $2\%$ of the main current is to be passed through a galvanometer of resistance $G$,then the resistance of the shunt will be