જો $|x| < 1$ હોય,તો $y = \sin^{-1}\left(\frac{2x}{1+x^2}\right)$ માટે $\frac{dy}{dx}$ શોધો.

  • A
    $\frac{2}{1+x^2}$
  • B
    $-\frac{2}{1+x^2}$
  • C
    $\frac{1}{1+x^2}$
  • D
    $-\frac{1}{1+x^2}$

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Similar Questions

જો $y = \sin^{-1} \left( \frac{\sqrt{1+x} + \sqrt{1-x}}{2} \right)$ હોય,તો $\frac{dy}{dx} = $

જો $x \neq n \pi, x \neq(2 n+1) \frac{\pi}{2}, n \in Z$ હોય,તો $\frac{\sin ^{-1}(\cos x)+\cos ^{-1}(\sin x)}{\tan ^{-1}(\cot x)+\cot ^{-1}(\tan x)}$ ની કિંમત શું થાય?

જો $\alpha = \cos^{-1}\left(\frac{3}{5}\right)$ અને $\beta = \tan^{-1}\left(\frac{1}{3}\right)$,જ્યાં $0 < \alpha, \beta < \frac{\pi}{2}$,તો $\alpha - \beta$ ની કિંમત શોધો.

$\theta \in \left(0, \frac{\pi}{2}\right)$ માટે, $\operatorname{sech}^{-1}(\cos \theta)$ ની કિંમત શોધો.

સાબિત કરો કે $\sin ^{-1} \frac{3}{5}-\sin ^{-1} \frac{8}{17}=\cos ^{-1} \frac{84}{85}$

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