Find a cubic polynomial with the sum,sum of the product of its zeroes taken two at a time,and the product of its zeroes as $2, -7, -14$ respectively.

(A) Let the cubic polynomial be $p(x) = ax^3 + bx^2 + cx + d$ and its zeroes be $\alpha, \beta,$ and $\gamma$.
The relationships between the coefficients and the zeroes are given by:
$1.$ Sum of zeroes: $\alpha + \beta + \gamma = -b/a = 2/1$
$2.$ Sum of the product of zeroes taken two at a time: $\alpha\beta + \beta\gamma + \gamma\alpha = c/a = -7/1$
$3.$ Product of zeroes: $\alpha\beta\gamma = -d/a = -14/1$
Comparing the values,we get $a = 1, b = -2, c = -7,$ and $d = 14$.
Substituting these values into the general form $ax^3 + bx^2 + cx + d$,we get the polynomial:
$p(x) = x^3 - 2x^2 - 7x + 14$.