Find the maximum number of atoms in the follo | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The number of atoms is calculated as: $	ext{Number of atoms} = \frac{	ext{mass}}{	ext{molar mass}} 	imes N_A 	imes 	ext{atomicity}$.$(i)$ $1

Vedclass · Accepted Answer

$(iii)$

Vedclass · Answer

(C) The number of atoms is calculated as: $	ext{Number of atoms} = \frac{	ext{mass}}{	ext{molar mass}} 	imes N_A 	imes 	ext{atomicity}$.$(i)$ $1 \ g$ $Au$: $\frac{1}{197} 	imes N_A \approx 0.00507 	imes N_A$ atoms.$(ii)$ $1 \ g$ $Na$: $\frac{1}{23} 	imes N_A \approx 0.04347 	imes N_A$ atoms.$(iii)$ $1 \ g$ $Li$: $\frac{1}{7} 	imes N_A \approx 0.14285 	imes N_A$ atoms.$(iv)$ $1 \ g$ $Cl_2$: $\frac{1}{71} 	imes N_A 	imes 2 \approx 0.02816 	imes N_A$ atoms.Comparing the values,$1 \ g$ $Li$ has the maximum number of atoms.

Find the maximum number of atoms in the following:
$(i)$ $1 \ g$ $Au_{(s)}$
$(ii)$ $1 \ g$ $Na_{(s)}$
$(iii)$ $1 \ g$ $Li_{(s)}$
$(iv)$ $1 \ g$ $Cl_{2(g)}$

Similar Questions

The number of moles and volume in $56 \ g$ of nitrogen $(N_2)$ are respectively:

Which gas among the following contains the maximum number of molecules at $STP$? (Molar masses in $g \ mol^{-1}$: $CO_{2}=44, Ar=39.9, CH_{4}=16, O_{2}=32$)

Two bulbs $B_1$ and $B_2$ contain $10 \ g$ each of $O_2$ and $O_3$ respectively. Which bulb contains a greater number of molecules and atoms?

The maximum number of molecules is present in

At $STP$,the moles of oxygen in $2.8 \ L$ of $CO_2$ gas is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module

Find the maximum number of atoms in the following:$(i)$ $1 \ g$ $Au_{(s)}$$(ii)$ $1 \ g$ $Na_{(s)}$$(iii)$ $1 \ g$ $Li_{(s)}$$(iv)$ $1 \ g$ $Cl_{2(g)}$