Find the products (C) and (E) in the followin | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) $1$. Wurtz reaction of $n$-propyl bromide $(CH_3CH_2CH_2Br)$ with $Na$ gives $n$-hexane $(A)$: $2CH_3CH_2CH_2Br + 2Na \rightarrow CH_3CH_2CH_2CH_2

Vedclass · Accepted Answer

Benzene hexachloride,Benzylidyne trichloride

Vedclass · Answer

(C) $1$. Wurtz reaction of $n$-propyl bromide $(CH_3CH_2CH_2Br)$ with $Na$ gives $n$-hexane $(A)$: $2CH_3CH_2CH_2Br + 2Na \rightarrow CH_3CH_2CH_2CH_2CH_2CH_3 + 2NaBr$.$2$. Aromatization of $n$-hexane over $Cr_2O_3/Al_2O_3$ at $773 \ K$ gives benzene $(B)$: $C_6H_{14} \rightarrow C_6H_6 + 4H_2$.$3$. Benzene $(B)$ reacts with $Cl_2$ in the presence of $UV$ light (addition reaction) to form benzene hexachloride $(C)$: $C_6H_6 + 3Cl_2 \xrightarrow{UV} C_6H_6Cl_6$.$4$. Benzene $(B)$ undergoes Friedel-Crafts alkylation with $CH_3Cl/AlCl_3$ to form toluene $(D)$: $C_6H_6 + CH_3Cl \xrightarrow{AlCl_3} C_6H_5CH_3 + HCl$.$5$. Toluene $(D)$ reacts with $Cl_2/hv$ (free radical substitution) to form benzylidyne trichloride $(E)$: $C_6H_5CH_3 + 3Cl_2 \xrightarrow{hv} C_6H_5CCl_3 + 3HCl$.

Similar Questions

The chemical system that is non-aromatic is

$A$ and $B$ are isomers. Product $B$ is: (Dewar's Benzene is $A$)

In the above reaction,' $X$ ' is:

Which of the following is a hydrocarbon?

Write down the products of ozonolysis of $1,2-$dimethylbenzene ($o-$xylene). How does the result support the Kekul\text{é} structure for benzene?

Vedclass Test Series

Exam Paper Generator

Online Exam Module