Find the L.C.M. of the polynomials 30 x^{2}+1 | vedclass

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(B) First,factorize the first polynomial: $30 x^{2}+13 x-3 = 30 x^{2}+18 x-5 x-3 = 6 x(5 x+3)-1(5 x+3) = (5 x+3)(6 x-1)$.Next,factorize the second pol

Vedclass · Accepted Answer

$(5 x-3)^{2}(5 x+3)(6 x-1)$

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(B) First,factorize the first polynomial: $30 x^{2}+13 x-3 = 30 x^{2}+18 x-5 x-3 = 6 x(5 x+3)-1(5 x+3) = (5 x+3)(6 x-1)$.Next,factorize the second polynomial: $25 x^{2}-30 x+9 = 25 x^{2}-15 x-15 x+9 = 5 x(5 x-3)-3(5 x-3) = (5 x-3)^{2}$.The $L.C.M.$ is the product of the highest powers of all prime factors present in the expressions.Therefore,$L.C.M. = (5 x-3)^{2}(5 x+3)(6 x-1)$.

Find the $L.C.M.$ of the polynomials $30 x^{2}+13 x-3$ and $25 x^{2}-30 x+9$.

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