Find the HCF and LCM of the following pair of | vedclass

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Question

(A) Step $1$: Find the prime factorization of $510$ and $92$.$510 = 2 	imes 3 	imes 5 	imes 17$$92 = 2^2 	imes 23$Step $2$: Find $HCF$ and $LCM$.$

Vedclass · Accepted Answer

$HCF = 2, LCM = 23460$

Vedclass · Answer

(A) Step $1$: Find the prime factorization of $510$ and $92$.$510 = 2 	imes 3 	imes 5 	imes 17$$92 = 2^2 	imes 23$Step $2$: Find $HCF$ and $LCM$.$HCF = 2^1 = 2$$LCM = 2^2 	imes 3 	imes 5 	imes 17 	imes 23 = 23460$Step $3$: Verify the relationship $HCF 	imes LCM = 	ext{product of the two numbers}$.$HCF 	imes LCM = 2 	imes 23460 = 46920$$	ext{Product of numbers} = 510 	imes 92 = 46920$Since $46920 = 46920$,the relationship is verified.

Find the $HCF$ and $LCM$ of the following pair of integers $510$ and $92$ and verify that $HCF \times LCM = \text{product of the two numbers}$.

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