Find the area of the sector of a circle with radius $4\, cm$ and of angle $30^{\circ}$. Also,find the area of the corresponding major sector (in $cm^2$) (Use $\pi = 3.14$).

(N/A) Given radius $r = 4\, cm$ and central angle $\theta = 30^{\circ}$.
Area of the sector $= \frac{\theta}{360^{\circ}} \times \pi r^{2}$
$= \frac{30}{360} \times 3.14 \times 4 \times 4\, cm^{2}$
$= \frac{1}{12} \times 3.14 \times 16\, cm^{2} = \frac{50.24}{12}\, cm^{2} \approx 4.19\, cm^{2}$.
Area of the corresponding major sector $= \pi r^{2} - \text{Area of minor sector}$
$= (3.14 \times 4^{2}) - 4.19\, cm^{2}$
$= (3.14 \times 16) - 4.19\, cm^{2}$
$= 50.24 - 4.19 = 46.05\, cm^{2} \approx 46.1\, cm^{2}$.