Find the energy of the third stationary orbit | vedclass

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(C) In Bohr's model of the hydrogen atom, the energy of the $n^{th}$ orbit is given by the formula: $E_n = \frac{E_1}{n^2}$, where $E_1$ is the energy

Vedclass · Accepted Answer

$-E/9 	ext{ J}$

Vedclass · Answer

(C) In Bohr's model of the hydrogen atom, the energy of the $n^{th}$ orbit is given by the formula: $E_n = \frac{E_1}{n^2}$, where $E_1$ is the energy of the ground state $(n=1)$.Given that the ground state energy $E_1 = -E 	ext{ J}$.For the third stationary orbit, $n = 3$.Substituting the values into the formula: $E_3 = \frac{E_1}{3^2} = \frac{-E}{9} 	ext{ J}$.Therefore, the energy of the third stationary orbit is $-E/9 	ext{ J}$.

Find the energy of the third stationary orbit of Bohr's model of the hydrogen atom if the energy of the ground state is $-E \text{ J}$.

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