Find the gravitational force between two ston | vedclass

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(D) Given: Mass of each stone, $m_1 = m_2 = 2 \,kg$.Separation distance, $r = 1 \,m$.Universal gravitational constant, $G = 6.67 	imes 10^{-11} \,N \

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$2.67 	imes 10^{-10} \,N$

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(D) Given: Mass of each stone, $m_1 = m_2 = 2 \,kg$.Separation distance, $r = 1 \,m$.Universal gravitational constant, $G = 6.67 	imes 10^{-11} \,N \cdot m^2/kg^2$.According to Newton's law of gravitation, the force $F$ is given by $F = \frac{G m_1 m_2}{r^2}$.Substituting the values: $F = \frac{6.67 	imes 10^{-11} 	imes 2 	imes 2}{1^2}$.$F = 6.67 	imes 10^{-11} 	imes 4$.$F = 26.68 	imes 10^{-11} \,N = 2.668 	imes 10^{-10} \,N$.Rounding to the nearest value, $F \approx 2.67 	imes 10^{-10} \,N$.

Find the gravitational force between two stones, each of mass $2 \,kg$ and separated by a distance $1 \,m$ in vacuum.

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