Find the maximum and minimum values of the function $f(x) = 9x^{2} + 12x + 2$.

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(D) The given function is $f(x) = 9x^{2} + 12x + 2$.
We can rewrite this by completing the square:
$f(x) = (3x)^{2} + 2(3x)(2) + 2^{2} - 2^{2} + 2$
$f(x) = (3x + 2)^{2} - 4 + 2$
$f(x) = (3x + 2)^{2} - 2$.
Since $(3x + 2)^{2} \geq 0$ for all $x \in \mathbb{R}$,the minimum value of $(3x + 2)^{2}$ is $0$.
Therefore,the minimum value of $f(x)$ is $0 - 2 = -2$,which occurs when $3x + 2 = 0$,i.e.,$x = -\frac{2}{3}$.
As $x \to \infty$,$f(x) \to \infty$,so the function does not have a maximum value.

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Similar Questions

Let $\alpha$ and $\beta$ be the roots of the quadratic equation $a x^2+b x+c=0$. Observe the lists given below:
List-$I$List-$II$
$(i)$ $\alpha = \beta$$(A)$ $(ac^2)^{1/3} + (a^2c)^{1/3} + b = 0$
$(ii)$ $\alpha = 2\beta$$(B)$ $2b^2 = 9ac$
$(iii)$ $\alpha = 3\beta$$(C)$ $b^2 = 6ac$
$(iv)$ $\alpha = \beta^2$$(D)$ $3b^2 = 16ac$
$(E)$ $b^2 = 4ac$
$(F)$ $(ac^2)^{1/3} + (a^2c)^{1/3} = b$

The correct match of List-$I$ from List-$II$ is:

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