Find the mean and the median of the observati | vedclass

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(A) Step $1$: To find the mean, sum all the observations and divide by the total number of observations.Sum $= 72 + 15 + 28 + 31 + 32 + 51 + 44 + 43 +

Vedclass · Accepted Answer

Mean $= 42, 	ext{Median} = 43$

Vedclass · Answer

(A) Step $1$: To find the mean, sum all the observations and divide by the total number of observations.Sum $= 72 + 15 + 28 + 31 + 32 + 51 + 44 + 43 + 62 = 378$.Total number of observations $(n) = 9$.Mean $= \frac{378}{9} = 42$.Step $2$: To find the median, arrange the observations in ascending order.Ordered data: $15, 28, 31, 32, 43, 44, 51, 62, 72$.Since $n = 9$ (which is odd), the median is the value at the $\frac{n+1}{2}$-th position.Median $= \frac{9+1}{2} = 5	ext{-th position}$.The $5	ext{-th}$ value in the ordered list is $43$.Therefore, Mean $= 42$ and Median $= 43$.

Find the mean and the median of the observations: $72, 15, 28, 31, 32, 51, 44, 43$ and $62$.

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