If the marks obtained by the $20$ students are $6, 4, 9, 5, 9, 3, 7, 7, 5, 6, 9, 4, 10, 10, 4, 3, 6, 7, 9, 9$,then the mode of this data is .............

Let $m$ be the mid-point and $l$ be the upper class limit of a class in a continuous frequency distribution. The lower class limit of the class is:

$A$ grouped frequency table with class intervals of equal sizes using $250-270$ ($270$ not included in this interval) as one of the class intervals is constructed for the following data:
$268, 220, 368, 258, 242, 310, 272, 342$
$310, 290, 300, 320, 319, 304, 402, 318$
$406, 292, 354, 278, 210, 240, 330, 316$
$406, 215, 258, 236$
The frequency of the class $310-330$ is:

$A$ die is thrown $1000$ times and the outcomes were recorded as follows:

Outcome	$1$	$2$	$3$	$4$	$5$	$6$
Frequency	$180$	$150$	$160$	$170$	$150$	$190$

If the die is thrown once more,then the probability that it shows $5$ is:

Find the mean,the median,and the mode of the observations:
$33, 92, 55, 90, 35, 77, 58, 41, 80, 64, 46$

$A$ football player scored the following number of goals in $10$ matches:
$1, 3, 2, 5, 8, 6, 1, 4, 7, 9$
Since the number of matches is $10$ (an even number),the median is calculated as:
Median $= \frac{5^{\text{th}} \text{ observation} + 6^{\text{th}} \text{ observation}}{2}$
$= \frac{8 + 6}{2} = 7$
Is this the correct answer? If not,why?