Find the mean deviation about the mean for th | vedclass

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(B) The given data is $4, 7, 8, 9, 10, 12, 13, 17$.The mean of the data,$\bar{x} = \frac{4+7+8+9+10+12+13+17}{8} = \frac{80}{8} = 10$.The deviations o

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$3$

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(B) The given data is $4, 7, 8, 9, 10, 12, 13, 17$.The mean of the data,$\bar{x} = \frac{4+7+8+9+10+12+13+17}{8} = \frac{80}{8} = 10$.The deviations of the respective observations from the mean $\bar{x}$,i.e.,$|x_{i} - \bar{x}|$,are:$|4-10| = 6$$|7-10| = 3$$|8-10| = 2$$|9-10| = 1$$|10-10| = 0$$|12-10| = 2$$|13-10| = 3$$|17-10| = 7$The mean deviation about the mean is given by:$M.D.(\bar{x}) = \frac{\sum_{i=1}^{8} |x_{i} - \bar{x}|}{8}$$M.D.(\bar{x}) = \frac{6 + 3 + 2 + 1 + 0 + 2 + 3 + 7}{8} = \frac{24}{8} = 3$.

${x_i}$	$2$	$5$	$6$	$8$	$10$	$12$
${f_i}$	$2$	$8$	$10$	$7$	$8$	$5$

Find the mean deviation about the mean for the data $4, 7, 8, 9, 10, 12, 13, 17$.

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