Find the mean of the following frequency dist | vedclass

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(D) To find the mean,we first calculate the class mark $(x_i)$ for each interval,where $x_i = \frac{	ext{Lower Limit} + 	ext{Upper Limit}}{2}$.
$1$

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$38$

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(D) To find the mean,we first calculate the class mark $(x_i)$ for each interval,where $x_i = \frac{	ext{Lower Limit} + 	ext{Upper Limit}}{2}$.
$1$. For $21-25$,$x_1 = 23$,$f_1 = 18$,$f_1x_1 = 414$.
$2$. For $26-30$,$x_2 = 28$,$f_2 = 32$,$f_2x_2 = 896$.
$3$. For $31-35$,$x_3 = 33$,$f_3 = 30$,$f_3x_3 = 990$.
$4$. For $36-40$,$x_4 = 38$,$f_4 = 40$,$f_4x_4 = 1520$.
$5$. For $41-45$,$x_5 = 43$,$f_5 = 25$,$f_5x_5 = 1075$.
$6$. For $46-50$,$x_6 = 48$,$f_6 = 15$,$f_6x_6 = 720$.
$7$. For $51-55$,$x_7 = 53$,$f_7 = 40$,$f_7x_7 = 2120$.
Sum of frequencies $(\sum f_i)$ = $18 + 32 + 30 + 40 + 25 + 15 + 40 = 200$.
Sum of products $(\sum f_ix_i)$ = $414 + 896 + 990 + 1520 + 1075 + 720 + 2120 = 7735$.
Mean $(\bar{x})$ = $\frac{\sum f_ix_i}{\sum f_i} = \frac{7735}{200} = 38.675$.

Class	$21-25$	$26-30$	$31-35$	$36-40$	$41-45$	$46-50$	$51-55$
Frequency	$18$	$32$	$30$	$40$	$25$	$15$	$40$

Class	$200-299$	$300-399$	$400-499$	$500-599$	$600-699$	$700-799$	$800-899$
Frequency	$3$	$61$	$118$	$139$	$126$	$151$	$2$

Class (seconds)	$13.8-14.0$	$14.0-14.2$	$14.2-14.4$	$14.4-14.6$	$14.6-14.8$	$14.8-15.0$
Frequency	$2$	$4$	$5$	$71$	$48$	$20$

Find the mean of the following frequency distribution:

Class $21-25$ $26-30$ $31-35$ $36-40$ $41-45$ $46-50$ $51-55$

Frequency $18$ $32$ $30$ $40$ $25$ $15$ $40$

(in $.675$)

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Find the mean of the following frequency distribution: Class $21-25$ $26-30$ $31-35$ $36-40$ $41-45$ $46-50$ $51-55$ Frequency $18$ $32$ $30$ $40$ $25$ $15$ $40$ (in $.675$)