For a given frequency distribution,n=100, A=2 | vedclass

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(B) The formula for the mean using the assumed mean method is given by $\bar{x} = A + \frac{\Sigma f_{i} d_{i}}{\Sigma f_{i}}$,where $\Sigma f_{i} = n

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(B) The formula for the mean using the assumed mean method is given by $\bar{x} = A + \frac{\Sigma f_{i} d_{i}}{\Sigma f_{i}}$,where $\Sigma f_{i} = n$.Given that $\bar{x} = 20$,$A = 20$,and $n = 100$.Substituting these values into the formula: $20 = 20 + \frac{\Sigma f_{i} d_{i}}{100}$.Subtracting $20$ from both sides,we get $0 = \frac{\Sigma f_{i} d_{i}}{100}$.Therefore,$\Sigma f_{i} d_{i} = 0 	imes 100 = 0$.

Class	$10-20$	$20-30$	$30-40$	$40-50$	$50-60$	$60-70$	$70-80$
Frequency	$6$	$10$	$5$	$6$	$4$	$2$	$2$

For a given frequency distribution,$n=100, A=20$ and $\bar{x}=20$. Then,$\Sigma f_{i} d_{i}=\ldots \ldots \ldots . .$

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