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(A) Given: Arc length $l = 37.4 \, cm$ and central angle $	heta = 60^{\circ}$.First, convert the angle from degrees to radians: $	heta = 60 	imes \

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$35.7$

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(A) Given: Arc length $l = 37.4 \, cm$ and central angle $	heta = 60^{\circ}$.First, convert the angle from degrees to radians: $	heta = 60 	imes \frac{\pi}{180} = \frac{\pi}{3} \, 	ext{radians}$.Using the formula for arc length $l = r	heta$, where $r$ is the radius, we have $r = \frac{l}{	heta}$.Substituting the values: $r = \frac{37.4}{\pi / 3} = \frac{37.4 	imes 3}{\pi}$.Using $\pi = \frac{22}{7}$, we get $r = \frac{37.4 	imes 3 	imes 7}{22}$.$r = \frac{112.2 	imes 7}{22} = \frac{785.4}{22} = 35.7 \, cm$.

Find the radius of the circle in which a central angle of $60^{\circ}$ intercepts an arc of length $37.4 \, cm$ (use $\pi = \frac{22}{7}$). (in $cm$)

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