Find the rate of formation of $NO_{2(g)}$ in the following reaction.
$2 N_2 O_{5(g)} \rightarrow 4 NO_{2(g)} + O_{2(g)}$
$\left[ \frac{-d[N_2 O_5]}{dt} = 0.02 \ mol \ dm^{-3} \ s^{-1} \right]$
$2 N_2 O_{5(g)} \rightarrow 4 NO_{2(g)} + O_{2(g)}$
$\left[ \frac{-d[N_2 O_5]}{dt} = 0.02 \ mol \ dm^{-3} \ s^{-1} \right]$
- A$0.01 \ mol \ dm^{-3} \ s^{-1}$
- B$0.02 \ mol \ dm^{-3} \ s^{-1}$
- C$0.03 \ mol \ dm^{-3} \ s^{-1}$
- D$0.04 \ mol \ dm^{-3} \ s^{-1}$
Explore More
Similar Questions
In the hydrolysis reaction of butyl chloride,the concentration of reactant at $600 \ s$ is determined using a tangent at $t_2 = 800 \ s$ and $t_1 = 400 \ s$. Given the concentrations $[R_2] = 0.0165 \ mol \ L^{-1}$ and $[R_1] = 0.037 \ mol \ L^{-1}$,calculate the instantaneous rate $r_{ins}$ at $600 \ s$.
Medium
View SolutionFor the reaction $H_{2(g)} + I_{2(g)} \rightleftharpoons 2HI_{(g)}$,the rate of reaction is expressed as:
MediumAIPMT 1997
View SolutionFor the reaction,$N_2 + 3H_2 \rightarrow 2NH_3,$ if $\frac{d[NH_3]}{dt} = 2 \times 10^{-4} \ mol \ L^{-1} \ s^{-1},$ the value of $-\frac{d[H_2]}{dt}$ would be .................. $mol \ L^{-1} \ s^{-1}$.
MediumAIPMT 2009
View SolutionFor a reaction,$2A + B \rightarrow 2C$,the rate of disappearance of $A$ is $0.076 \ mol \ dm^{-3} \ s^{-1}$. What is the rate of disappearance of $B$?
In the following reaction: $xA \to yB$,$\log \left[ -\frac{d[A]}{dt} \right] = \log \left[ \frac{d[B]}{dt} \right] + \log 2$,where the negative sign indicates the rate of disappearance of the reactant. Thus,$x : y$ is:
Vedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo