Find the ratio in which the line segment joining the points $(4, 8, 10)$ and $(6, 10, -8)$ is divided by the $YZ$-plane.

If $A (1, 2, -1)$ and $B (-1, 0, 1)$ are two points,then the coordinates of the point which divides $AB$ externally in the ratio $1 : 2$ are:

If $Q(\alpha, \beta, \gamma)$ is the harmonic conjugate of the point $P(0, -7, 1)$ with respect to the line segment joining the points $A(2, -5, 3)$ and $B(-1, -8, 0)$,then $\alpha - \beta + \gamma =$

The point dividing the line segment joining $(3, -2, 1)$ and $(-2, 3, 11)$ in the ratio $2:3$ is

If the $x$-coordinate of a point $P$ on the line joining the points $Q(2,2,1)$ and $R(5,1,-2)$ is $4$, then the $z$-coordinate of $P$ is

Given that the points $A(1,0,1), B(2,-1,3)$ and $C(3,-2,5)$ are collinear,then the ratio in which $C$ divides $\overline{AB}$ from the side of $A$ is $...$