Find the roots of the following quadratic equ | vedclass

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Question

(A) Given equation: $2x^{2} - x + \frac{1}{8} = 0$Multiply the entire equation by $8$ to remove the fraction:$16x^{2} - 8x + 1 = 0$Now,factorise the q

Vedclass · Accepted Answer

$x = \frac{1}{4}, \frac{1}{4}$

Vedclass · Answer

(A) Given equation: $2x^{2} - x + \frac{1}{8} = 0$Multiply the entire equation by $8$ to remove the fraction:$16x^{2} - 8x + 1 = 0$Now,factorise the quadratic expression by splitting the middle term:$16x^{2} - 4x - 4x + 1 = 0$Group the terms:$4x(4x - 1) - 1(4x - 1) = 0$$(4x - 1)(4x - 1) = 0$$(4x - 1)^{2} = 0$Setting the factor to zero:$4x - 1 = 0$$4x = 1$$x = \frac{1}{4}$Thus,the roots of the equation are $x = \frac{1}{4}, \frac{1}{4}$.

Find the roots of the following quadratic equation by factorisation:
$2x^{2} - x + \frac{1}{8} = 0$

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Find the roots of the following quadratic equation by factorisation:$2x^{2} - x + \frac{1}{8} = 0$