Find the slope of the line passing through the points $(3, -2)$ and $(-1, 4)$.

Reduce the following equation into intercept form and find its intercepts on the axes: $4x - 3y = 6$.

If the straight line $ax + by + c = 0$ always passes through $(1, -2),$ then $a, b, c$ are

The lines $2x + 3y = 6$ and $2x + 3y = 8$ cut the $X$-axis at $A$ and $B$,respectively. $A$ line $L$ drawn through the point $(2, 2)$ meets the $X$-axis at $C$ in such a way that the abscissae of $A, B,$ and $C$ are in arithmetic progression. Then,the equation of the line $L$ is

$A$ line $L$ intersects the lines $3x - 2y - 1 = 0$ and $x + 2y + 1 = 0$ at the points $A$ and $B$. If the point $(1, 2)$ bisects the line segment $AB$ and $\frac{x}{a} + \frac{y}{b} = 1$ is the equation of the line $L$,then $a + 2b + 1 = $

The equation of the line which passes through the point $(-4, 3)$ and whose portion intercepted between the axes is divided internally in the ratio $5 : 3$ by this point is: