Find the speed of a body at the ground when it falls freely from a height of $2\,m$. $(g = 10\,ms^{-2})$

$A$ stone is dropped from the top of a tall building and after $2 \,s$ another stone is thrown vertically downwards with a velocity $5 \,m/s$ from the same point. The distance from the top of the building at which the second stone overtakes the first is . . . . . . $\left(g=10 \,m/s^2\right)$ (in $\,m$)

$A$ packet is dropped from a balloon which is going upwards with a velocity of $12 \, m/s$. The velocity of the packet after $2 \, s$ will be ........ $m/s$.

$A$ body is released from the top of a tower $H$ metre high. It takes $t$ seconds to reach the ground. The height of the body $\frac{t}{2}$ seconds after release is

If a particle takes $t$ seconds less and acquires a velocity of $v \ ms^{-1}$ more in falling through the same distance (starting from rest) on two planets where the accelerations due to gravity are $2g$ and $8g$ respectively,then $v=$

$A$ body is dropped from a certain height $h$ ($h$ is very large) and a second body is thrown downward with a velocity of $5 \, m/s$ simultaneously. What will be the difference in the heights of the two bodies after $3 \, s$?