Find the sum of an AP of 40 terms whose first | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The sum of an $AP$ is given by the formula $S_n = \frac{n}{2}(a_1 + a_n)$,where $n$ is the number of terms,$a_1$ is the first term,and $a_n$ is th

Vedclass · Accepted Answer

$7100$

Vedclass · Answer

(C) The sum of an $AP$ is given by the formula $S_n = \frac{n}{2}(a_1 + a_n)$,where $n$ is the number of terms,$a_1$ is the first term,and $a_n$ is the last term.Given:Number of terms $n = 40$First term $a_1 = 80$Last term $a_{40} = 275$Substituting these values into the formula:$S_{40} = \frac{40}{2}(80 + 275)$$S_{40} = 20(355)$$S_{40} = 7100$Thus,the sum of the $40$ terms is $7100$.

Find the sum of an $AP$ of $40$ terms whose first and last terms are $80$ and $275$.

Similar Questions

If the sum of the roots of the quadratic equation $ax^2 + bx + c = 0, (abc \neq 0)$ is equal to the sum of the squares of their reciprocals,then $a/c, b/a, c/b$ are in

If $a_1 = a_2 = 2$ and $a_n = a_{n-1} - 1$ for $n > 2$,then $a_5$ is:

If the first term of a $G.P.$ is $5$ and the common ratio is $-5$,then which term is $3125$ (in $^{th}$)?

If $\frac{a + bx}{a - bx} = \frac{b + cx}{b - cx} = \frac{c + dx}{c - dx}, (x \ne 0)$,then $a, b, c, d$ are in

If $a, b, c$ are in $G.P.$,then

Vedclass Test Series

Exam Paper Generator

Online Exam Module