Find the sum of the order and degree of the d | vedclass

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Question

(B) The given differential equation is $y = x(\frac{dy}{dx})^3 + \frac{d^2y}{dx^2}$.The order of a differential equation is the order of the highest d

Vedclass · Accepted Answer

$3$

Vedclass · Answer

(B) The given differential equation is $y = x(\frac{dy}{dx})^3 + \frac{d^2y}{dx^2}$.The order of a differential equation is the order of the highest derivative present in the equation. Here,the highest derivative is $\frac{d^2y}{dx^2}$,so the order is $2$.The degree of a differential equation is the power of the highest derivative when the equation is expressed as a polynomial in derivatives. Here,the power of the highest derivative $\frac{d^2y}{dx^2}$ is $1$.Thus,the order is $2$ and the degree is $1$.The sum of the order and degree is $2 + 1 = 3$.Therefore,option $(B)$ is correct.

Find the sum of the order and degree of the differential equation $y = x(\frac{dy}{dx})^3 + \frac{d^2y}{dx^2}$.

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