Find the time required for 50,Hz alternating | vedclass

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Question

(D) The instantaneous current is given by $I = I_0 \sin(\omega t)$.To change from zero to maximum value,the current must go from $I = 0$ to $I = I_0$.

Vedclass · Accepted Answer

$5\, ms$

Vedclass · Answer

(D) The instantaneous current is given by $I = I_0 \sin(\omega t)$.To change from zero to maximum value,the current must go from $I = 0$ to $I = I_0$.Thus,$\sin(\omega t) = 1$.This implies $\omega t = \frac{\pi}{2}$.Substituting $\omega = 2\pi f$,we get $2\pi f t = \frac{\pi}{2}$.Given frequency $f = 50\,Hz$,the equation becomes $2\pi(50)t = \frac{\pi}{2}$.$100\pi t = \frac{\pi}{2}$.$t = \frac{1}{200}\,s = 0.005\,s = 5\,ms$.

Find the time required for $50\,Hz$ alternating current to change its value from zero to maximum value.

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