Find the time required for a 50 text{ Hz} alt | vedclass

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(A) The instantaneous current is given by $i = i_{m} \sin(\omega t)$.At the $rms$ value, $i = i_{rms} = \frac{i_{m}}{\sqrt{2}}$.Substituting this into

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$2.5$

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(A) The instantaneous current is given by $i = i_{m} \sin(\omega t)$.At the $rms$ value, $i = i_{rms} = \frac{i_{m}}{\sqrt{2}}$.Substituting this into the equation: $\frac{i_{m}}{\sqrt{2}} = i_{m} \sin(\omega t)$.$\sin(\omega t) = \frac{1}{\sqrt{2}}$, which implies $\omega t = \frac{\pi}{4}$.Since $\omega = 2 \pi f$, we have $2 \pi f t = \frac{\pi}{4}$.$t = \frac{1}{8f}$.Given $f = 50 	ext{ Hz}$, $t = \frac{1}{8 	imes 50} = \frac{1}{400} 	ext{ s}$.$t = 0.0025 	ext{ s} = 2.5 	ext{ ms}$.

Find the time required for a $50 \text{ Hz}$ alternating current to reach its $rms$ value from zero. (in $\text{ ms}$)

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