cos ^{-1}left(frac{1}{2}right)+2 sin ^{-1}lef | vedclass

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Question

(B) ધારો કે $\cos ^{-1}\left(\frac{1}{2}\right)=x$. તેથી,$\cos x=\frac{1}{2}=\cos \left(\frac{\pi}{3}\right)$. તેથી,$\cos ^{-1}\left(\frac{1}{2}\right

Vedclass · Accepted Answer

$\frac{2 \pi}{3}$

Vedclass · Answer

(B) ધારો કે $\cos ^{-1}\left(\frac{1}{2}ight)=x$. તેથી,$\cos x=\frac{1}{2}=\cos \left(\frac{\pi}{3}ight)$. તેથી,$\cos ^{-1}\left(\frac{1}{2}ight)=\frac{\pi}{3}$. ધારો કે $\sin ^{-1}\left(\frac{1}{2}ight)=y$. તેથી,$\sin y=\frac{1}{2}=\sin \left(\frac{\pi}{6}ight)$. તેથી,$\sin ^{-1}\left(\frac{1}{2}ight)=\frac{\pi}{6}$. આ કિંમતોને પદાવલિમાં મૂકતા: $\cos ^{-1}\left(\frac{1}{2}ight)+2 \sin ^{-1}\left(\frac{1}{2}ight)=\frac{\pi}{3}+2 	imes \frac{\pi}{6} = \frac{\pi}{3}+\frac{\pi}{3} = \frac{2 \pi}{3}$.

$\cos ^{-1}\left(\frac{1}{2}\right)+2 \sin ^{-1}\left(\frac{1}{2}\right)$ ની કિંમત શોધો.

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