Five capacitors of capacitances C_1 = C_2 = C | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The circuit is a balanced Wheatstone bridge because $\frac{C_1}{C_2} = \frac{C_4}{C_3} = \frac{10}{10} = 1$.Since the bridge is balanced, no charg

Vedclass · Accepted Answer

$5 \mu F$, $250 \mu C$ on $C_1, C_2, C_3, C_4$ and $0 \mu C$ on $C_5$

Vedclass · Answer

(D) The circuit is a balanced Wheatstone bridge because $\frac{C_1}{C_2} = \frac{C_4}{C_3} = \frac{10}{10} = 1$.Since the bridge is balanced, no charge flows through the central capacitor $C_5$.Therefore, the circuit simplifies to two parallel branches, each containing two capacitors in series.The left branch consists of $C_1$ and $C_2$ in series, and the right branch consists of $C_4$ and $C_3$ in series.Equivalent capacitance of each branch: $C_{	ext{branch}} = \frac{10 	imes 10}{10 + 10} = 5 \mu F$.Total equivalent capacitance: $C_{	ext{eq}} = 5 \mu F + 5 \mu F = 10 \mu F$.Total charge supplied by the battery: $Q = C_{	ext{eq}}V = 10 \mu F 	imes 50 \ V = 500 \mu C$.Since the branches are identical, the charge divides equally: $250 \mu C$ flows through each branch.Thus, $250 \mu C$ is on each capacitor $C_1, C_2, C_3, C_4$ and $0 \mu C$ is on $C_5$.

Five capacitors of capacitances $C_1 = C_2 = C_3 = C_4 = 10 \mu F$ and $C_5 = 2.5 \mu F$ are connected as shown, along with a battery of $50 \ V$. Find the equivalent capacitance and the charge on the capacitors.

Similar Questions

Choose the correct statement for the given capacitor arrangement. (All the $6$ capacitors are of same capacitance)

Calculate the charge on the capacitor in the steady state. (in $\mu C$)

When a parallel plate capacitor is connected to a source of constant potential difference,

$A$ capacitor of $50 \,\mu {F}$ is connected in a circuit as shown in the figure. The charge on the upper plate of the capacitor is $......\,\mu {C} .$

Vedclass Test Series

Exam Paper Generator

Online Exam Module