The five valence electrons of P^{15} are labe | vedclass

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(B) The electronic configuration of $P$ $(Z=15)$ is $1s^2 2s^2 2p^6 3s^2 3p^3$.The valence electrons are in $3s$ and $3p$ orbitals.For the $3s$ orbita

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$AB$

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(B) The electronic configuration of $P$ $(Z=15)$ is $1s^2 2s^2 2p^6 3s^2 3p^3$.The valence electrons are in $3s$ and $3p$ orbitals.For the $3s$ orbital,the electrons are $A$ and $B$. Since they are in the same orbital $(n=3, l=0, m=0)$,they share three quantum numbers $(n, l, m)$ and differ only in spin $(s)$. Given $s_B = +\frac{1}{2}$,then $s_A = -\frac{1}{2}$. Thus,$A$ and $B$ share three quantum numbers.For the $3p$ orbital,the electrons are $X, Y, Z$. They are in different sub-orbitals $(m = -1, 0, +1)$,so they have different $m$ values. Thus,they do not share three quantum numbers.Therefore,the group of electrons sharing three identical quantum numbers is $AB$.

The five valence electrons of $P^{15}$ are labeled as $A, B, X, Y, Z$ as shown in the figure. If the spin quantum number of $B$ and $Z$ is $+\frac{1}{2}$,identify the group of electrons that share three identical quantum numbers.

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