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(B) According to Raoult's Law,the total pressure of a binary ideal solution is given by $P_{total} = X_A P_A^o + X_B P_B^o$. Since $X_A + X_B = 1$,we

Vedclass · Accepted Answer

$P_{total} = P_B^o + (P_A^o - P_B^o)X_A$

Vedclass · Answer

(B) According to Raoult's Law,the total pressure of a binary ideal solution is given by $P_{total} = X_A P_A^o + X_B P_B^o$. Since $X_A + X_B = 1$,we can substitute $X_A = 1 - X_B$. $P_{total} = (1 - X_B) P_A^o + X_B P_B^o$ $P_{total} = P_A^o - X_B P_A^o + X_B P_B^o$ $P_{total} = P_A^o + X_B(P_B^o - P_A^o)$. Alternatively,substituting $X_B = 1 - X_A$: $P_{total} = X_A P_A^o + (1 - X_A) P_B^o$ $P_{total} = X_A P_A^o + P_B^o - X_A P_B^o$ $P_{total} = P_B^o + X_A(P_A^o - P_B^o)$. Comparing this with the given options,option $B$ is correct.

For a binary ideal liquid solution,the total pressure of the solution is given as:

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