(A) The rate law for the reaction is given by $r = k[A]^1[B]^1$.For the first experiment: $0.10 = k(20)(0.5)$ $\Rightarrow 0.10 = 10k$ $\Rightarrow k

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(A) The rate law for the reaction is given by $r = k[A]^1[B]^1$.For the first experiment: $0.10 = k(20)(0.5)$ $\Rightarrow 0.10 = 10k$ $\Rightarrow k = 0.01 \ L \ mol^{-1} \ s^{-1}$.For the second experiment: $0.40 = k(x)(0.5)$. Substituting $k = 0.01$: $0.40 = 0.01(x)(0.5)$ $\Rightarrow 0.40 = 0.005x$ $\Rightarrow x = 80 \ mol \ L^{-1}$.For the third experiment: $0.80 = k(40)(y)$. Substituting $k = 0.01$: $0.80 = 0.01(40)(y)$ $\Rightarrow 0.80 = 0.4y$ $\Rightarrow y = 2 \ mol \ L^{-1}$.Therefore,the values are $x = 80$ and $y = 2$.

Class 12 Chemistry Chemical Kinetics Rate law , Rate constant , Order of Reaction and Molecularity

Medium

For a chemical reaction $A + B \rightarrow \text{Product}$,the order is $1$ with respect to $A$ and $B$.
Rate $(mol \ L^{-1} \ s^{-1})$ $[A]$ $(mol \ L^{-1})$ $[B]$ $(mol \ L^{-1})$
$0.10$ $20$ $0.5$
$0.40$ $x$ $0.5$
$0.80$ $40$ $y$

What is the value of $x$ and $y$?

Rate $(mol \ L^{-1} \ s^{-1})$	$[A]$ $(mol \ L^{-1})$	$[B]$ $(mol \ L^{-1})$
$0.10$	$20$	$0.5$
$0.40$	$x$	$0.5$
$0.80$	$40$	$y$

JEE MAIN 2023 All JEE MAIN

A
$80$ and $2$
B
$40$ and $4$
C
$160$ and $4$
D
$80$ and $4$

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Class 12

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Chemical Kinetics

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Rate law , Rate constant , Order of Reaction and Molecularity

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For a reaction between substances $A$ and $B$,the rate law is given by: $\text{Rate} = K[A]^n[B]^m$. If the concentration of $A$ is doubled and the concentration of $B$ is halved,what will be the ratio of the new rate to the original rate?

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For a chemical reaction $A + B \rightarrow \text{Product}$,the order is $1$ with respect to $A$ and $B$.Rate $(mol \ L^{-1} \ s^{-1})$$[A]$ $(mol \ L^{-1})$$[B]$ $(mol \ L^{-1})$$0.10$$20$$0.5$$0.40$$x$$0.5$$0.80$$40$$y$What is the value of $x$ and $y$?

Similar Questions

For the reaction $XA + YB \rightarrow mp + nq$,the rate is given by $\text{Rate} = K[A]^c[B]^d$. What is the overall order of the reaction?

Which of the following is an example of a pseudo unimolecular reaction?

The mechanism of the reaction $2NO_2 + F_2 \to 2NO_2F$ is given by:$(i)$ $NO_2 \xrightarrow{slow} NO + O$$(ii)$ $F_2 + O + NO \xrightarrow{fast} NO_2F + F$$(iii)$ $F + NO_2 \xrightarrow{fast} NO_2F$Select the correct statement.

When the temperature increases from $300 \, K$ to $310 \, K$,the rate of reaction increases by $2.3$ times. If the rate constant at $300 \, K$ is $x$,then the rate constant at $310 \, K$ will be equal to .......

For a reaction between substances $A$ and $B$,the rate law is given by: $\text{Rate} = K[A]^n[B]^m$. If the concentration of $A$ is doubled and the concentration of $B$ is halved,what will be the ratio of the new rate to the original rate?

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For a chemical reaction $A + B \rightarrow \text{Product}$,the order is $1$ with respect to $A$ and $B$.
Rate $(mol \ L^{-1} \ s^{-1})$ $[A]$ $(mol \ L^{-1})$ $[B]$ $(mol \ L^{-1})$
$0.10$ $20$ $0.5$
$0.40$ $x$ $0.5$
$0.80$ $40$ $y$

What is the value of $x$ and $y$?

The mechanism of the reaction $2NO_2 + F_2 \to 2NO_2F$ is given by:
$(i)$ $NO_2 \xrightarrow{slow} NO + O$
$(ii)$ $F_2 + O + NO \xrightarrow{fast} NO_2F + F$
$(iii)$ $F + NO_2 \xrightarrow{fast} NO_2F$
Select the correct statement.