For a common base circuit,if $\frac{I_C}{I_E} = 0.98$,then the current gain for a common emitter circuit will be:

The transfer ratio of a transistor is $50$. The input resistance of the transistor when used in the common-emitter configuration is $1 \; k\Omega$. The peak value of the collector current for an $A.C.$ input voltage of $0.01 \; V$ peak is:

In an $n-p-n$ transistor circuit,the collector current is $20 \, mA$. If $90 \%$ of the emitted electrons reach the collector,calculate the emitter current and base current.

$A$ $CE$ amplifier has a voltage gain of $G$. The transistor used has a transconductance of $0.03 \ mho$ and a current gain of $25$. If this transistor is replaced by another transistor with a transconductance of $0.02 \ mho$ and a current gain of $20$,the new voltage gain will be ........

If collector current is $120\, mA$,base current is $2\, mA$,and resistance gain is $3$,what is the power gain?

For a transistor amplifier in a common-emitter configuration,given the load resistance $R_L = 1 \ k\Omega$,$h_{fe} = 50$,and $h_{oe} = 25 \ \mu A/V$,calculate the current gain $(A_i)$.