The transfer ratio of a transistor is $50$. The input resistance of the transistor when used in the common-emitter configuration is $1 \; k\Omega$. The peak value of the collector current for an $A.C.$ input voltage of $0.01 \; V$ peak is:

In an $n-p-n$ transistor circuit,the collector current is $10 \, mA$. If $90 \%$ of the electrons reach the collector,then the emitter current will be:

For a given transistor,if $\alpha = I_C / I_E = 0.96$,then the current gain $\beta$ is:

In the given transistor circuit,the base current is $35 \ \mu A$. If the value of $V_{BE}$ is negligible,what is the value of $R_b$ in $k\Omega$?

In common emitter configuration of a transistor amplifier, $r_i$, $R_L$ and $\beta$ represent the input resistance, load resistance, and the a.c. current gain, respectively. The voltage gain $A_V$ and power gain $A_P$ are represented in magnitude by which of the following expressions?

An $n-p-n$ transistor is connected in common-emitter configuration as shown in the figure. If the collector current is $5 \text{ mA}$,$V_{BE} = 0.6 \text{ V}$,$V_{CE} = 3 \text{ V}$,and the common-emitter current amplification factor $\beta = 50$,then the values of $R_1$ and $R_2$ are respectively.