In an $n-p-n$ transistor circuit,the collector current is $10 \, mA$. If $90 \%$ of the electrons reach the collector,then the emitter current will be:

The given transistor operates in the saturation region. What should be the value of $V_{BB}$ (in $Volt$)?
$(R_{out} = 200 \, \Omega, R_{in} = 100 \, k\Omega, V_{CC} = 3 \, V, V_{BE} = 0.7 \, V, \beta = 200)$

$A$ $CE$ amplifier has a voltage gain of $G$. The transistor used has a transconductance of $0.03 \ mho$ and a current gain of $25$. If this transistor is replaced by another transistor with a transconductance of $0.02 \ mho$ and a current gain of $20$,the new voltage gain will be ........

$A$ transistor having $\alpha = 0.99$ is used in a common base amplifier. If the load resistance is $4.5 \, k\Omega$ and the dynamic resistance of the emitter junction is $50 \, \Omega$,the voltage gain of the amplifier will be:

In a common emitter configuration with suitable bias,it is given that $R_L$ is the load resistance and $R_{BE}$ is the small signal dynamic resistance (input side). Then,the voltage gain,current gain,and power gain are given,respectively,by: [$\beta$ is the current gain,$I_B$,$I_C$,$I_E$ are respectively base,collector,and emitter currents]

The output characteristics of an $n-p-n$ transistor represent, ($I_C =$ collector current, $V_{CE} =$ potential difference between collector and emitter, $I_B =$ base current, $V_{BB} =$ voltage given to base, $V_{BE} =$ the potential difference between base and emitter)